Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as
1
and 0
respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is
2
.
Note: m and n will be at most 100.
public class Solution { public int uniquePathsWithObstacles(int[][] obstacleGrid) { int m = obstacleGrid.length; if(0 == m) return 0; int n = obstacleGrid[0].length; if(0 == n) return 0; int[] dp = new int[m]; if( 1 == obstacleGrid[0][0]) return 0; dp[0] = 1; for(int i = 0; i < n; ++i){ for(int j = 0; j < m; ++j){ if(1 == obstacleGrid[j][i]){ dp[j] = 0; }else{ if(0 == j){ dp[j] = dp[j]; }else{ dp[j] += dp[j-1]; } } } } return dp[m-1]; } }
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