Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as
1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is
2.
Note: m and n will be at most 100.
public class Solution {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
int m = obstacleGrid.length;
if(0 == m)
return 0;
int n = obstacleGrid[0].length;
if(0 == n)
return 0;
int[] dp = new int[m];
if( 1 == obstacleGrid[0][0])
return 0;
dp[0] = 1;
for(int i = 0; i < n; ++i){
for(int j = 0; j < m; ++j){
if(1 == obstacleGrid[j][i]){
dp[j] = 0;
}else{
if(0 == j){
dp[j] = dp[j];
}else{
dp[j] += dp[j-1];
}
}
}
}
return dp[m-1];
}
}
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