Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
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public class Solution { int keepDec(int i, int[] nums){ --i; while(i>=0 && nums[i]==nums[i + 1]){ --i; } return i; } int keepInc(int i, int[] nums){ ++i; while(i= 0 && y < len){ int sum = nums[i] + nums[x] + nums[y]; if(Math.abs(sum - target) < Math.abs(res - target)){ res = sum; } if(sum == target){ return target; } else if( sum > target){ y = keepDec(y, nums); }else{ x = keepInc(x, nums); } } i = keepInc(i, nums); } return res; } }
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